A hyperelliptic curve admits a double covering map onto the projective line, i.e., the Riemann sphere if one works over the complex numbers. This map is usually called the canonical map. Therefore, a curve is hyperelliptic if it is not isomorphic onto its image under the canonical map. Meaning, under this map it is not a projective embedding. Non-hyperelliptic curves are a projective embedding under the canonical map. An Euler characteristic computation (Riemann Hurwitz formula) shows that any hyperelliptic curve of genus g \geq 2 is ramified at 2g+2 points. Since we know that there exists an action of PSL(2,C) acting on P^1 by (x,y,z) -> (0,1,\infty) it follows that any hyperelliptic curve is of the form x(x-1)(x-a_i) where i=1,...,2g-1. To distinguish between (I always forgot about the names) complex and real hyperelliptic curves is simple to distinguish between whether or not roots of its equation lying at infinity. However, I'am doing research to low genus hyperelliptic curves; so be patiented and a good reference will appear soon :P
 Quote by mathwonk
an algebraic curve is often studied by its field of rational functions. A curve is hyperelliptic if that field is a quadratic extension of the rational function field K(t).
In geometric terms, a hyperelliptic curve has a degree two map onto the projective line P^1. All curves which do not are non hyperelliptic. Over the complexes say, all genus two curves are hyperelliptic, since the riemann roch theorem implies their canonical map is of degree two onto P^1. Hyperelliptic curves also exist in every positive genus, and for all genera g at least 2, the canonical map gives a degree two map to a copy of P^1 embedded in P^(g-1)
David Mumford's book Tata Lectures on Theta, book II, chapter 3, is an excellent source at least for hyperelliptic curves and their jacobians over the complex field.
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