Predator vs. prey - trouble

by edge
Tags: predator, prey, trouble
 P: 42 (2) $$\frac{dy}{dt}=qy(1-\frac{y}{d})$$ This means $$(\frac{1}{y}+\frac{1}{d-y})\frac{dy}{dt}=q$$ Integrate both sides to var t, you will get $$ln\frac{y}{d-y}=qt+C_0, C_0 = const$$ $$\frac{y}{d-y}=C_1 e^q^t$$ Take y out and substitute it into the equation of x and similarly try to solve that equation (x,t). Then Find lim of x when t goes to infinity, this is what you are being asked to do.. I don't know if I has made any mistake in this post but hehhe you check it again yourself.