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Voltage Drop Between Sender & Receiver .....( help needed ASAP , Thanks in advance ) 
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#1
Jan2212, 11:21 AM

P: 18

hello every body I'm EE student and I'm new member here ... in a deep need for your help & knowledge
I'm doing some reading about the power transmitted from the sender to the receiver end , As we all know that when we have an inductive load we need to connect capacitors on parallel to the load in order to compensate the drop in voltage My question is ; what keeps the current to flow from the supply to the load ( as long as there is no longer difference in voltage ) .... Is that because the Vs ( Sending voltage end ) and Vr ( receiving voltage end ) will "almost" have same magnitude but different phase angle !? Another question ; what makes the voltage to drop in the very first place exactly !? the load !? Regards. 


#2
Jan2312, 05:17 AM

Sci Advisor
Thanks
PF Gold
P: 12,186

Hello.
Why a current with no voltage drop (DC or AC)? For an ideal connecting wire the voltage drop is zero, too. Does that bother you? Reason: the resistance is vanishingly small so, for any current flowing through it, the voltage drop will also be vanishingly small. (V = IR) Draw yourself a schematic diagram of the situation, including a Source resistance, a Load (resistance plus some series L) and parallel C. Where is the L and where is the C? Calculate what the Load will look like with C = 0 and when the C and L resonate? See how much Power is dissipated in the Load under those two conditions. 


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