- #1
aaaa202
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Let r = √(x^2+y^2+z^2)
One can easily show that [itex]\nabla[/itex]r= [itex]\vec{r}[/itex]/r.
But I'm having a hard time understanding what this means geometrically - who can help? :)
One can easily show that [itex]\nabla[/itex]r= [itex]\vec{r}[/itex]/r.
But I'm having a hard time understanding what this means geometrically - who can help? :)