How to solve this algebraically?


by e^(i Pi)+1=0
Tags: algebraically, solve
e^(i Pi)+1=0
e^(i Pi)+1=0 is offline
#1
Apr10-12, 05:40 AM
P: 232
1. The problem statement, all variables and given/known data
125,000=79,770.26(1+[itex]\frac{.045}{n}[/itex])10n


2. Relevant equations



3. The attempt at a solution
I'm not sure how to use a logarithm with this, or if it's even possible. I know that n=12, I just don't know how to solve for it.
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D H
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#2
Apr10-12, 06:35 AM
Mentor
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Quote Quote by e^(i Pi)+1=0 View Post
I know that n=12, I just don't know how to solve for it.
n = 12 is a solution for sufficiently large values of 12. n=12 (exactly) is not a solution. n≈12.06655246 is a solution.

You can't solve this analytically. You will need to resort to numerical techniques.
e^(i Pi)+1=0
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#3
Apr10-12, 06:44 AM
P: 232
Thanks, I wasn't sure if I was missing something. It's not exactly 12 here because the 79,770.26 is rounded.

Joffan
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#4
Apr10-12, 02:03 PM
P: 329

How to solve this algebraically?


79,770.62 is closer, and 79,770.63 is closer still for n=12.
Mentallic
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#5
Apr10-12, 08:10 PM
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Quote Quote by D H View Post
n = 12 is a solution for sufficiently large values of 12
Curious3141
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#6
Apr11-12, 09:33 AM
HW Helper
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Quote Quote by D H View Post
n = 12 is a solution for sufficiently large values of 12.
Nice!


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