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Torsion test simulation |
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| Apr26-12, 08:58 PM | #1 |
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Torsion test simulation
Hi all,
I am simulating torsion tests (after being successful with tension and compression tests). For tension and compression, I got a good comparsion with experimental and behaviour in tension is same as in compression (of course leaving the necking part). For torsion tests, I have taken equivalent tensile stress = shear stress*sqrt(3) and equivalent tensile strain as = shear strain / sqrt (3). This is based on Von Mises criteria. But I have a problem, doing this I find that there is a variation of about 6-8 % from the uniaxial tension test and compression test . IS there some approxiamtion in Von Mises criteria of equivalent tensile stress and strain? I tried to google and more and this what I found: http://books.google.co.in/books?id=F...strain&f=false From this ; am I correct below (you can read the abstractabove as well): “Torsion equivalent stresses obtained using Von Misesrelationship (as I have done) are 6.5% lower than those obtained using BishopHill formulation which is more accurate” So, can we say that torsion equivalent stresses will bearound 6.5% less than that obtained using uniaxial tension ? Warm regards, Vishal |
| May1-12, 10:00 PM | #2 |
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Please can anyone help?
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