Angular Momentum

by naestibill
Tags: angular, momentum
naestibill is offline
May4-12, 01:36 PM
P: 2
Considering a Rigid Body/Angular Momentum/Torque

We know that Torque(ext) = dL/dt

Now with respect to stationary point S:
L(s, cm) = Ʃ(ρi x mivi)
and that dL(cm)/dt = Ʃτ(ext, CM)

Now with respect to ANY point, P, that is accelerating:
L(s,p) = L(cm) + ρ(cm) x Mv(cm)
And hence,
Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)
Ʃτ(ext, p) = dL(rel_cm)/dt + ρ(cm) x Ma(cm)

Can someone explain to me why this happens?:
Why this happens? : Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)

Phys.Org News Partner Physics news on
Physicists consider implications of recent revelations about the universe's first light
Vacuum ultraviolet lamp of the future created in Japan
Grasp of SQUIDs dynamics facilitates eavesdropping
haruspex is offline
May4-12, 04:46 PM
Sci Advisor
HW Helper
Thanks ∞
P: 9,212
If you would take the trouble to describe all your variables you've a better chance of a response.

Register to reply

Related Discussions
Angular Velocity and Spin/Orbital Angular Momentum of Jupiter Astrophysics 2
Conserved angular momentum: finding angular velocities of drums as a function of time Introductory Physics Homework 2
Angular Momentum - Find angular velocity of a hanging bar after a collision Introductory Physics Homework 1
Physics Rotating Disk, Moment of Inertia, Angular Momentum, Angular Velocity Introductory Physics Homework 12
Angular momentum and orbital angular momentum problems Introductory Physics Homework 3