Register to reply

Angular Momentum

by naestibill
Tags: angular, momentum
Share this thread:
naestibill
#1
May4-12, 01:36 PM
P: 2
Considering a Rigid Body/Angular Momentum/Torque

We know that Torque(ext) = dL/dt

Now with respect to stationary point S:
L(s, cm) = Ʃ(ρi x mivi)
and that dL(cm)/dt = Ʃτ(ext, CM)

Now with respect to ANY point, P, that is accelerating:
L(s,p) = L(cm) + ρ(cm) x Mv(cm)
And hence,
Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)
Ʃτ(ext, p) = dL(rel_cm)/dt + ρ(cm) x Ma(cm)

Can someone explain to me why this happens?:
Why this happens? : Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)

Thanks
Phys.Org News Partner Physics news on Phys.org
UCI team is first to capture motion of single molecule in real time
And so they beat on, flagella against the cantilever
Tandem microwave destroys hazmat, disinfects
haruspex
#2
May4-12, 04:46 PM
Homework
Sci Advisor
HW Helper
Thanks
P: 9,928
If you would take the trouble to describe all your variables you've a better chance of a response.


Register to reply

Related Discussions
Angular Velocity and Spin/Orbital Angular Momentum of Jupiter Astronomy & Astrophysics 2
Conserved angular momentum: finding angular velocities of drums as a function of time Introductory Physics Homework 2
Angular Momentum - Find angular velocity of a hanging bar after a collision Introductory Physics Homework 1
Physics Rotating Disk, Moment of Inertia, Angular Momentum, Angular Velocity Introductory Physics Homework 12
Angular momentum and orbital angular momentum problems Introductory Physics Homework 3