Is this equivalent to the Pythagorean Theorem?

Quine!

So I was reading up on the Pythagoreans, and I came across this page: http://www.math.ufl.edu/~rcrew/texts/pythagoras.html.

I don't see the reasoning behind this statement.

"Since AB=AD+DB, adding these equations yields

A(B²)=A(C²)+C(B²)
which is the Pythagorean theorem."

I tried some simple algebra on this statement and couldn't get Pythag to fall out of it. Can someone figure out a derivation for this?

Muphrid

That's not what the page says. It says,

[tex]AB^2 = AC^2 + CB^2[/tex]

A, B, and C are not variables. [itex]AB[/itex] represents the length between points A and B. You should read [itex]AB^2[/itex] as a single length being squared.

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Muphrid	That's not what the page says. It says, [tex]AB^2 = AC^2 + CB^2[/tex] A, B, and C are not variables. [itex]AB[/itex] represents the length between points A and B. You should read [itex]AB^2[/itex] as a single length being squared.