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Current = nqvA

by Googl
Tags: current, nqva
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Googl
#1
Nov21-12, 04:38 PM
P: 111
Hi all,

I was wondering whether someone might help further understand the following equation for current. I mean get a good picture of how each valuable relates to each other and how they come to represent current.

Current = nqvA

Thanks. I know what each valuable represents but I can't seem to get a good picture how the equal represents current especially; Where time is taken into account since current is the rate of charge carriers/electrons.

I hope I have made my self clear.

Thanks.
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Googl
#2
Nov21-12, 04:45 PM
P: 111
Oops. No need I understand it now.

...but I would appreciate any replies just to make sure.
sophiecentaur
#3
Nov21-12, 05:12 PM
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Quote Quote by Googl View Post
Hi all,

I was wondering whether someone might help further understand the following equation for current. I mean get a good picture of how each valuable relates to each other and how they come to represent current.

Current = nqvA

Thanks. I know what each valuable represents but I can't seem to get a good picture how the equal represents current especially; Where time is taken into account since current is the rate of charge carriers/electrons.

I hope I have made my self clear.

Thanks.
Could you please say what the variables in that equation all stand for? Where did you find that equation and what was the context? I have a problem with balancing it, dimensionally if the variables are what I assume they are.

willem2
#4
Nov21-12, 05:24 PM
P: 1,395
Current = nqvA

Quote Quote by sophiecentaur View Post
Could you please say what the variables in that equation all stand for? Where did you find that equation and what was the context? I have a problem with balancing it, dimensionally if the variables are what I assume they are.
n = density of charge carriers (1/m^3)
q = charge of a charge carrier. (coulomb)
v = average speed of charge carriers. (m/s)
A = area of cross-section of wire m^2.

If you multiply them together you get coulomb/s = Ampere
sophiecentaur
#5
Nov21-12, 05:36 PM
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Just checking we're reading from the same hymn sheet..
This is the 'well known' relationship in which the dimensions are the same each side (that should be reassuring). The way it's derived is to consider a cylinder with of area A and unit length, moving at average speed v. The number of charges in the cylinder will be n times the volume, which is nA (times one, the unit length) so the charge in it will be nqA (per unit length) and the number of charges passing a point in one second will be nqAv. That's I, the current.
OK?
Ratch
#6
Nov21-12, 07:49 PM
P: 315
Googl,

I remember it as:

n or p (holes or electrons) = charge carriers
q = charge per carrier --1.6E-19 C/(electron or hole)
v = velocity
A = area

So n*q*v*A or p*q*v*A equals current

Sometimes J (current density) is used. J = I/A = q*(p or n)*v.

EDIT: Sorry, I should have written in the first line, "concentration of n or p (holes or electrons) = charge carriers/m^3 .

Ratch


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