# Finally, discuss some physical limitations that might ...

by Jamin2112
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 P: 920 1. The problem statement, all variables and given/known data Part (d) of problem 1 here: http://faculty.washington.edu/joelzy...02_W13_hw4.pdf 2. Relevant equations I have (I(t) I'(t))T = cos(t/√(LC))k1 + sin(t/√(LC))k2, some k1, k2 ε ℂ2 for my solution and so I know that decreasing the value of LC increases the ticking frequency of this clock. 3. The attempt at a solution But I'm at a loss for what to put for this "discuss some physical limitations" thing. Thoughts?
 HW Helper Thanks PF Gold P: 4,856 For one thing - do you think this clock will run forever? Even if so, does the current level stay constant or does it get harder to detect over time? Do the values of R, C and L change in any way over time?
P: 920
 Quote by rude man For one thing - do you think this clock will run forever?
Theoretically, yes.

 Even if so, does the current level stay constant or does it get harder to detect over time?
Well, it oscillates, since current is V = RI, R is constant, I is oscillating.

 Do the values of R, C and L change in any way over time?
I don't really know since I'm not an electrical engineer

 Thanks P: 5,801 Finally, discuss some physical limitations that might ... I do not see any dependence of the solution on R. How come?
P: 920
 Quote by voko I do not see any dependence of the solution on R. How come?
If we want it to tick with a constant frequency, then we want the node to be a center, so we want R=0. Right? We want I(t)=0 periodically.
HW Helper
Thanks
PF Gold
P: 4,856
 Quote by Jamin2112 Theoretically, yes. Well, it oscillates, since current is V = RI, R is constant, I is oscillating. I don't really know since I'm not an electrical engineer
Does it seem reasonale to assume that whatever circuit you use to detect the zero crossings of the current has a limitation as to how low the current can be before it can't tell the difference between that low level and zero?

And BTW you can't have R = 0 in real life. Besides, the problem specifies a resistor.

And FYI R, C and L do change over time & environment. That's why crystal oscillators are used in your PC!
Thanks
P: 5,801
 Quote by Jamin2112 If we want it to tick with a constant frequency, then we want the node to be a center, so we want R=0. Right? We want I(t)=0 periodically.
Do you think it is physically possible to have R = 0? The circuit is called LRC for a reason.
P: 920
 Quote by voko Do you think it is physically possible to have R = 0? The circuit is called LRC for a reason.
Isn't my intuition right, though, that we want the vector field of (I I')T to be something circling the origin forever?
 Thanks P: 5,801 Is that possible with R > 0?

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