Meaning of Square of four vector potential

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The square of the four vector potential, expressed as (\phi,A)^2 = \phi^2 - A^2, has significant implications in physics, particularly regarding its Lorentz invariance. If the invariant is timelike, it represents the scalar potential in a frame where the vector position is zero, while a spacelike invariant indicates the magnitude of the vector potential when the scalar potential is zero. The interpretation of this invariant can be complex due to the frame variance of gauge conditions, particularly outside the Lorentz gauge. Additionally, the potential can be adjusted by adding a constant vector without altering the underlying physics, allowing for flexibility in its interpretation. Understanding these aspects is crucial for deeper insights into electromagnetic theory and relativity.
merrypark3
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The square of the four vector potential.

(\phi,A)^2=\phi ^2 - A^2

What's the physical meaning of this lorentz invariant?
 
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If the invariant is timelike then it would be the scalar potential in a frame where the vector position was 0, and if the invariant is spacelike then it would be the magnitude of the vector potential in a frame where the scalar potential is 0. However, unless you are using the Lorentz gauge your gauge condition is frame variant so interpreting it becomes a little strange.
 
hi merrypark3! :smile:

you can add any constant vector to the potential without changing the physics …

so you can make that invariant anything you like! :wink:
 
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