Atom and its reaction while travelling in a magnetic field

AI Thread Summary
Atoms exhibit distinct behavior when traveling through a magnetic field, influenced by their magnetic moments, which are quantized. In the case of a hydrogen atom, the magnetic moment can adopt only two discrete orientations, leading to specific trajectories in a magnetic field. The angle of the atom's trajectory, or declination, is determined by the strength of the magnetic field and the atom's magnetic moment. This quantization is a fundamental aspect of quantum mechanics, illustrating the unique properties of atomic behavior in magnetic environments. Understanding these principles is crucial for experiments involving devices like the Stern-Gerlach analyzer.
radioactive8
Messages
46
Reaction score
0
Hello
I was reading a book about quantum mechanics and in some point it used as an example the reaction of the atom while its traveling through a magnetic field . So the author described an atom as a magnetic arrow ( which isn't complety right but he did that so he can reveal the truth afterwards and so we readers end up in a mathetical dead end in an experiment using a stern-gerlach analyser .. so he said That if we have a dissimilar magnetic field for example which its trend going up he said that according to the trend of the atom's arrow it will even travel up by μβ or down by μβ . So hear is my question : how can it have the same declination ?
2
 
Physics news on Phys.org
radioactive8 said:
So hear is my question : how can it have the same declination ?
2

By declination I imagine you mean the angle of the trajectory after the magnetic field with respect to the original direction of propagation. In that case, it is set by the strength of the magnetic field and the magnetic moment of the atom, which I imagine is here a hyrogen atom, which can take only two discrete values which are exactly opposite. This is the "quantum" in quantum mechanics: the magnetic moment is quantized and can only take a discrete set of values.
 
  • Like
Likes 1 person
More precisely, the magnitude of the magnetic moment is fixed, but its orientation can take on a discrete set of values (two in this case).
 
  • Like
Likes 1 person
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top