Power Input for Motor and Back EMF

AI Thread Summary
Back EMF in a motor increases with speed, reducing the current drawn when the motor operates at high speeds, particularly under light or no load conditions. This results in lower power requirements at high speeds, as the motor does not need to deliver significant mechanical power. Conversely, when a motor is stalled, it draws maximum electrical power but delivers no mechanical output. As the motor experiences load and slows down, back EMF decreases, allowing current and output power to increase. Understanding these dynamics is crucial for optimizing motor efficiency and performance.
psycho
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Hello everyone, I'm a bit confused about the power drawn by a motor. Since back emf reduces current when the motor is rotating at high speed, is it true that back emf reduces the power required at high speed? THX :D
 
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psycho said:
Hello everyone, I'm a bit confused about the power drawn by a motor. Since back emf reduces current when the motor is rotating at high speed, is it true that back emf reduces the power required at high speed? THX :D
Hi psycho. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Yes. At the higher speed back emf is greater, so current reduces. Of course, you'll only see such high range speeds when the motor is unloaded, or very lightly loaded, so it isn't being required to produce much mechanical power (compared to its full capabilitiy) under those conditions, anyway.
 
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Hello nascent, how about the power drawn by the motor? Is it Also minimum at highspeed and maximum when stall?
 
psycho said:
Hello nascent, how about the power drawn by the motor? Is it Also minimum at highspeed and maximum when stall?
If you operate your DC motor from a fixed voltage, then the motor draws maximum electrical power when stalled. Note, that when stalled the motor is delivering zero mechanical power to its shaft, ω=0.
 
Google dc motor efficiency curves and look at torque, current, rpm and power output (efficiency) curves.

When a motor is unloaded it spins at maximum rpm and draws little current and outputs no power. As you load it down it spins slower, draws more current and outputs more power. If the motor were 100% efficient, the Voltage X Current drawn would equal the output power. As the motor slows down due to load, the back emf reduces so the current (and output power) increases.
 
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