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Amar.alchemy
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Overhang of uniform blocks??
If you put a uniform block at the edge of a table. the center of the hlock must be over the table for the hlock not to fall off. (a) If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks together must be over the table. In terms of the length L of each block, what is the maximum overhang(see attached file) possible??
Xcm= Mx1+Mx2 / (M + M)
If i keep the bottom block on the table so that its CG lies at the right edge of the table, then using the above formula if i calculate the CG for both blocks, its CG also lies at the edge of the table...
Taking origin as the left edge of the bottom block...
[tex]
\[\begin{array}{l}
L/2 = (M(L/2) + Mx)/(M + M) \\
x = L/2 \\
\end{array}\]
[/tex]
kindly help me
Homework Statement
If you put a uniform block at the edge of a table. the center of the hlock must be over the table for the hlock not to fall off. (a) If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks together must be over the table. In terms of the length L of each block, what is the maximum overhang(see attached file) possible??
Homework Equations
Xcm= Mx1+Mx2 / (M + M)
The Attempt at a Solution
If i keep the bottom block on the table so that its CG lies at the right edge of the table, then using the above formula if i calculate the CG for both blocks, its CG also lies at the edge of the table...
Taking origin as the left edge of the bottom block...
[tex]
\[\begin{array}{l}
L/2 = (M(L/2) + Mx)/(M + M) \\
x = L/2 \\
\end{array}\]
[/tex]
kindly help me
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