- #1
margaret23
- 11
- 0
Show that Z3 X Z5 is isomorphic to Z15 (where Zn is like the intergers mod n)
i m not sure if i m proving it right.. if i first right out Z3 x Z5 ={(1x1), (1X2),(1x3),(1x4), (1X5), (2X1),(2x2),(2x3), (2x4), (2X5), (3x1), (3x3),(3x3),(3x4), (3X5)}
Z15={1,2,3...15}
both of which have 15 elements... there for they are in the same form?? therefore isomorphic??
i would appreciate any help
thanks
i m not sure if i m proving it right.. if i first right out Z3 x Z5 ={(1x1), (1X2),(1x3),(1x4), (1X5), (2X1),(2x2),(2x3), (2x4), (2X5), (3x1), (3x3),(3x3),(3x4), (3X5)}
Z15={1,2,3...15}
both of which have 15 elements... there for they are in the same form?? therefore isomorphic??
i would appreciate any help
thanks