- #1
serverxeon
- 101
- 0
I know the approach is to use conservation of angular momentum.
I also know that I am entirely free to pick which point I would like to calculate my L about. (Although calculating L about the CM will make it much easier, but I'd like to try otherwise)
So, if I were to calculate my L(after collision) about the left end of the rod, how would I express my L?
Am I able to do just L=Iω, where I is the modified [itex]I=\frac{1}{12} \times 2m\times l^{2}+ml^{2}[/itex]
The ω I get is then the answer I am looking for? It feels wrong to me.