- #1
chaotixmonjuish
- 287
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The kicker on a football team can give the ball an initial speed of 26.2 m/s. If he is to score a field goal from a point 42.2 m in front of goalposts whose horizontal bar is 3.75 m above the ground, what is the minimum and maximum angle above the horizontal he must kick the ball?
I figured out this much
ax=0
ay= -9.8
vx= sin(theta)*26.2
vy= cos(theta)*26.2
x= sin(theta)*26.2x
y= cos(theta)*26.2x-4.9x^2
and I think
3.75= cos(theta)*26.2x-4.9x^2
My first attempt at an answer yielded 5.06 and 26.something. I tried using arctan(3.75/42.2) to get an angle. I'm not really sure how to approach this problem since theta is missing.
I figured out this much
ax=0
ay= -9.8
vx= sin(theta)*26.2
vy= cos(theta)*26.2
x= sin(theta)*26.2x
y= cos(theta)*26.2x-4.9x^2
and I think
3.75= cos(theta)*26.2x-4.9x^2
My first attempt at an answer yielded 5.06 and 26.something. I tried using arctan(3.75/42.2) to get an angle. I'm not really sure how to approach this problem since theta is missing.
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