- #1
Telemachus
- 835
- 30
Homework Statement
Hi there. I'm not sure if this question corresponds to this subforum, but I think you must be more familiarized with it. The thing is I don't know how to get from:
[tex]M_x=(I_0-I)\dot\Psi^2\sin\theta\cos\theta+I_0\dot\Phi\dot\Psi\sin\theta[/tex]
to:
[tex]\dot\Psi=\displaystyle\frac{I_0\dot\Phi}{2(I-I_0)\cos\theta} \left[1\pm \left( {1-\displaystyle\frac{4M_x(I-I_0)\cos\theta}{I_0^2\dot\Phi^2\sin\theta}}\right)^{1/2}\right][/tex]
I don't know how to get Phi from the first, but this is the simplification given on my book, but I don't know which intermediate steps to give.
Bye, and thanks.