- #1
firyace
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Hi, I got a problem with something regarding to chemistry. How can you determine the pH of a solution with two Acids?
The question says that A 50.00 mL aqueous solution is made by mixing the following two solutions:
10.00mL 1x10^-9M HCl
50.00mL 1*10^-4 M CH3COOH (Ka= 1.8*10^-5)
a) What is the Cl^- in the 50.00mL solution?
b)What is the pH in the 50mL solution?
c) What is the [CH3COOH] in the 50mL solution?
thanks!
The question says that A 50.00 mL aqueous solution is made by mixing the following two solutions:
10.00mL 1x10^-9M HCl
50.00mL 1*10^-4 M CH3COOH (Ka= 1.8*10^-5)
a) What is the Cl^- in the 50.00mL solution?
b)What is the pH in the 50mL solution?
c) What is the [CH3COOH] in the 50mL solution?
thanks!