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mr.learnmore
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1. Water at T1=240 C and P1=16 MPa is at 2 km depth. A drilling hole with diameter 0.2 m has the water flowing up with mass flow rate at 2 kg/s. The hole is considered adiabatic(no heat transfer).
I need to find the following values at the top of the hole:
Enthalpy(h), temperature(T2), pressure(P2) and steam percentage(x) of the water.
There is no pipe friction. At the top of the hole there is a throttling valve which leads to further piping(so the pressure can not be considered to be 1 atm).
3. The Attempt at a Solution
The water is a compressed liquid in the beginning, so using saturated liquid values at T1 gives(from table):
v1=0.001229 m^3/kg
h1=1037.5 kJ/kg
The initial velocity is V =0.078241 m/s, using massflowrate = ρ*A*V.
The mass flow is steady, but as pressure drops with elevation the specific volume changes (I would think).
I'm not sure how to begin solving this, any ideas/hints are very welcome.
I need to find the following values at the top of the hole:
Enthalpy(h), temperature(T2), pressure(P2) and steam percentage(x) of the water.
There is no pipe friction. At the top of the hole there is a throttling valve which leads to further piping(so the pressure can not be considered to be 1 atm).
3. The Attempt at a Solution
The water is a compressed liquid in the beginning, so using saturated liquid values at T1 gives(from table):
v1=0.001229 m^3/kg
h1=1037.5 kJ/kg
The initial velocity is V =0.078241 m/s, using massflowrate = ρ*A*V.
The mass flow is steady, but as pressure drops with elevation the specific volume changes (I would think).
I'm not sure how to begin solving this, any ideas/hints are very welcome.