- #1
Juwane
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Every book that I have checked, it says the dx after the integrand is just there to remind us that it is the variable x that is being integrated. I however am trying to see some other meaning. There must be some reason why, when we integrate 2x, it is also multiplied by dx. I have tried real hard but couldn't come up with a reasonable explanation.
Maybe someone here can help me.
But first of all, answer this: Is the dx and the integrand being multiplied? For example, in [tex]\int dy = \int 2x dx[/tex], dx is being multiplied by 2x? I believe it is, since from [tex]\frac{dy}{dx} = 2x[/tex] we get [tex]dy=2x \cdot dx[/tex], then we integrate both sides.
Maybe someone here can help me.
But first of all, answer this: Is the dx and the integrand being multiplied? For example, in [tex]\int dy = \int 2x dx[/tex], dx is being multiplied by 2x? I believe it is, since from [tex]\frac{dy}{dx} = 2x[/tex] we get [tex]dy=2x \cdot dx[/tex], then we integrate both sides.
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