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Homework Statement
a) given, a + 5 and 2a-1, one is 40% greater than the other one, solve for a.
b) given, 5x[tex]^{4}[/tex] + 4x[tex]^{3}[/tex] + 3x[tex]^{2}[/tex] + Px + Q. When divided by x[tex]^{2}[/tex] - 1, you get a remainder of 0, solve for p and q.
c) given csc(6b + [tex]\frac{pi}{8}[/tex]) = sec(2b - [tex]\frac{pi}{8}[/tex]), solve for b.
Homework Equations
The Attempt at a Solution
please help, i can't get started on these three at all...
edit:
c) i know that cscx = 1/sinx and secx = 1/cosx, i then cross multiplied to get [tex]cos(2b-pi/8) = sin(6b+pi/8)...
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