- #1
Hussam Al-Tayeb
- 5
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If all I have given is that
1. Bacteria grows at a rate proportional to it's size.
2. It doubles in 2 days.
3. At 10 days, population is 1000.
I'm not given the initial bacteria count, I need help setting up the equation.
I did:
dy/dt = ky => dy/y = kdt => lny= kt + c => y=e^(kt) + c
y(10)= 1000 = e^(10k) + c
But I'm lost how to complete this. Any idea?
1. Bacteria grows at a rate proportional to it's size.
2. It doubles in 2 days.
3. At 10 days, population is 1000.
I'm not given the initial bacteria count, I need help setting up the equation.
I did:
dy/dt = ky => dy/y = kdt => lny= kt + c => y=e^(kt) + c
y(10)= 1000 = e^(10k) + c
But I'm lost how to complete this. Any idea?