- #1
T7
- 18
- 0
Hi,
This is a v. simple Q, but I have a mental block today (!).
The question is: What size must z be in the function f(z) to output the value of the integral I with an error of 0.1? What about an error of 0.01? Or 0.001?
I calculate I to be 0.6666666... recurring.
Now
f(3) = 0.8148148147
f(4) = 0.7500000000
f(5) = 0.72000000
f(7) = 0.693875508
f(8) = 0.687500000
f(9) = 0.6831275719
f(10) = 0.6800000000
etc.
By a 0.1 error, does it mean that the value of f(x) must fall within I ± 0.1? ie no more than (0.66666... + 0.1 =) 0.76666666... and no less than (0.66666... - 0.1 =) 0.5666666 ? ie. z=4 satisfies the requirement (?)
Cheers.
This is a v. simple Q, but I have a mental block today (!).
The question is: What size must z be in the function f(z) to output the value of the integral I with an error of 0.1? What about an error of 0.01? Or 0.001?
I calculate I to be 0.6666666... recurring.
Now
f(3) = 0.8148148147
f(4) = 0.7500000000
f(5) = 0.72000000
f(7) = 0.693875508
f(8) = 0.687500000
f(9) = 0.6831275719
f(10) = 0.6800000000
etc.
By a 0.1 error, does it mean that the value of f(x) must fall within I ± 0.1? ie no more than (0.66666... + 0.1 =) 0.76666666... and no less than (0.66666... - 0.1 =) 0.5666666 ? ie. z=4 satisfies the requirement (?)
Cheers.