- #1
Grant_
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I've tried to come up with a simple model for scissor lifts
and came to the conclusion that the force applied to the centre, by the screw must be the (payload + top arms)/tanθ
I set payload + top arms = 981 N
I then found the average value of the function by integrating from 15 to 90° and then dividing by pi/2-pi/12, and received an answer of 1013 N.
A regular lift would have an average value of 981 N - top arms. It seems like using a scissor lift requires more effort, is the only advance that you can apply a load sideways?
I'd appreciate any help.
Thanks
and came to the conclusion that the force applied to the centre, by the screw must be the (payload + top arms)/tanθ
I set payload + top arms = 981 N
I then found the average value of the function by integrating from 15 to 90° and then dividing by pi/2-pi/12, and received an answer of 1013 N.
A regular lift would have an average value of 981 N - top arms. It seems like using a scissor lift requires more effort, is the only advance that you can apply a load sideways?
I'd appreciate any help.
Thanks
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