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kartikwat
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Why does the potential drops when charge pass through a capacitors connected in series.
kartikwat said:@drakkith i am not getting what u r explaining
kartikwat said:https://www.dropbox.com/s/1t18mlwb3agnxq0/Screenshot_2014-07-15-15-41-35.png
What does the following paragraph convey on capacitors in series,i think it is not clear.
Don't use dropbox; instead, attach the diagram directly.kartikwat said:https://www.dropbox.com/s/1t18mlwb3agnxq0/Screenshot_2014-07-15-15-41-35.png
What does the following paragraph convey on capacitors in series,i think it is not clear.
kartikwat said:This is what i am trying to understand
A capacitor is an electronic component that stores electrical charge. It consists of two conductive plates separated by an insulating material, known as a dielectric.
When capacitors are connected in series, the total capacitance is reduced and the voltage drop across each capacitor is the same as the total voltage applied to the circuit. This is because the same amount of charge builds up on each plate of the capacitors, resulting in a decrease in total capacitance.
Potential drop refers to the decrease in voltage that occurs across each capacitor in a series circuit. This is due to the fact that the total voltage applied to the circuit is divided equally among all of the capacitors in the series, resulting in a decrease in voltage across each capacitor.
To calculate the potential drop across each capacitor in a series circuit, you can use the formula V = Q/C, where V is the voltage drop, Q is the charge stored on each capacitor, and C is the capacitance of each capacitor. This formula can also be used to calculate the total capacitance in a series circuit.
Capacitors in series are commonly used in electronic circuits to store and regulate electrical charge. They are also used in power factor correction to improve the efficiency of electric power transmission and distribution systems.