- #1
tkdiscoverer
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right now, I'm following the MIT thermodynamics video lecture.
I've gone thru
dU = [STRIKE]d[/STRIKE]w + [STRIKE]d[/STRIKE]q
([STRIKE]d[/STRIKE] for "is path dependent")
and
H = U + pV
But why is enthalpy a function of temperature and pressure?
is it because pV = nRT and thus, V = nRT/p, so we only need p and T to get V?
dH = ( [itex]\delta[/itex] H/ [itex]\delta[/itex] )TdT + ( [itex]\delta[/itex] H/ [itex]\delta[/itex] p)dp
but why not:
dH = ([itex]\delta[/itex]H/[itex]\delta[/itex] T)dT + ([itex]\delta[/itex]H/[itex]\delta[/itex]V)dV ?
Thanks! : D
I've gone thru
dU = [STRIKE]d[/STRIKE]w + [STRIKE]d[/STRIKE]q
([STRIKE]d[/STRIKE] for "is path dependent")
and
H = U + pV
But why is enthalpy a function of temperature and pressure?
is it because pV = nRT and thus, V = nRT/p, so we only need p and T to get V?
dH = ( [itex]\delta[/itex] H/ [itex]\delta[/itex] )TdT + ( [itex]\delta[/itex] H/ [itex]\delta[/itex] p)dp
but why not:
dH = ([itex]\delta[/itex]H/[itex]\delta[/itex] T)dT + ([itex]\delta[/itex]H/[itex]\delta[/itex]V)dV ?
Thanks! : D
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