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nms03
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Homework Statement
Compute for the value of pressure beneath the foot of a person after stomping. The person has a weight of 50kgs, supposed that there is a sensor beneath the foot of the person and after stomping the foot it records a 51.5 kg of weight. The area of the sensor is 2.5 square inch.
Stationary weight = 50 kgs
measured weight after stomping = 51.5 kg
Area of the pressure where change of weight is detected = 2. 5 square inch
Homework Equations
Pressure = Force / AreaForce = mass x acceleration
The Attempt at a Solution
Computing for the pressure upon stomping on the sensor is equivalent for Pressure = Force / Area.
I have an Area which is 2.5 square inch now,the problem is what is the applied force. Since I have a change of rate of the weight which 51.5 kgs from 50kgs. Can I consider this as the Force as 51.5kg/s/s.
Or Force equal to mass x acceleration. The mass would be the default weight that is 50kgs. Then the force is computed as (measured weight - actual weight) / actual weight. Leaving the acceleration as the unknown variable. If I proceed on this method... it would be
acceleration = force / mass
a = (51.5kg/s/s - 50 kg/s/s )/ 50kg
a =.03 s/s.
Then going back to the pressure formula P = F / A, P = (mass x acceleration) / area.
P = (51.5 kg /s/s x .03 s/s) / 2.5 square inch. Pressure is .618 Kg/ square inch.
Please help anyone.
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