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When getting phase angle difference, do amplitudes have to be positive 
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#1
Mar2114, 02:17 PM

P: 45

$$f(x)=32sin(x+60°)\quad and\quad g(x)=1.5sin(x+45°)$$
Would the phase angle difference here be 15° or is that incorrect? I think the amplitudes don't have to be the same but I'm not sure if they at least have to be both positive. 


#2
Mar2114, 03:37 PM

Sci Advisor
P: 6,027

sin(a) = sin(a+π). See what happens.



#3
Mar2114, 10:10 PM

P: 1

n = 180 and a<90, for sin(a) = sin(a+n)



#4
Mar2414, 11:38 AM

P: 45

When getting phase angle difference, do amplitudes have to be positive
$$1.5sin(x+45°)\\ =1.5sin(x+225°)$$
Here the phase angle difference is 165°. So which would be more correct? The phase angle difference is simply defined as the difference between the two phase angles in two sinusoids, right? So are they both right? 


#5
Mar2414, 03:33 PM

Sci Advisor
P: 6,027

When you look at the graphs, the phase difference is the difference between corresponding points (e.g. max) on the the two curves. Therefore they both need to expressed with the same sign. In this case 225° is the correct value for phase difference.



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