- #1
LD_90
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The acceleration of a particle moving at constant speed is perpendicular to its instantaneous velocity. How can I show this by using the fact that
d(v^2)/dt=d(v. v )/dt=0?
This doesn't seem like the most direct way to look at the concept. Help me out.
d(v^2)/dt=d(v. v )/dt=0?
This doesn't seem like the most direct way to look at the concept. Help me out.