Hess Law: Molar Enthelpy Change for Decomposition

In summary, the task for a chemistry report is to determine the molar enthalpy change for the decomposition of sodium hydrogen carbonate into sodium carbonate, CO(2) and water. This cannot be measured directly, so the reaction was carried out separately with HCL in excess. By using the equation of Heat = Mass * Specific Heat (c) * Delta T, the molar enthalpies for each reaction were calculated to be -0.971 kJ/mol and 1.267 kJ/mol, respectively. These values were then used to find the molar enthalpy change for the overall reaction, taking into account the amounts of materials used and the heat of solution.
  • #1
Tomtom
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Homework Statement


This is for a chemistry report. This is the task:
"Determine the molar enthalpy change for the decomposition of sodium hydrogen carbonate into sodium carbonate, CO(2) and water.
2NaHCO(3) -> Na(2)CO(3) + CO(2) + H(2)O
This enthalpy change cannot be measured directly".

Instead, we reacted NaHCO(3) and Na(2)CO(3) in separate containers with HCL (in excess (100 mL), about 1M).

We measured the temperature changes, and the masses of each solid/liquid.

For the NaHCO(3) reaction:
Mass(NaHCO(3)): 0.001021 kg ± 0.000001 kg
Mass(HCL): 0.100 ± 0.001 kg
Change in T = 1 K

For the Na(2)CO(3) reaction:
Mass(Na(2)CO(3)): 0.000905 kg ± 0.000001 kg
Mass(HCL): 0.100 ± 0.001 kg
Change in T = -0.3 K

Homework Equations


Nr 1: 2NaHCO(3) -> Na(2)CO(3) + CO(2) + H(2)O
Nr 2: NaHCO(3) + HCl -> NaCL + CO(2) + H(2)O
Nr 3: Na(2)CO(3) + HCl -> 2NaCL + CO(2) + H(2)O

Note: By multiplying equation 2 by two, reversing equation 3, and then adding them together, we get equation 1. This has to be done to the enthalpies I calculate in Part 3, too.

The Attempt at a Solution


My biggest problem is figuring out how to find the Molar Delta H in kJ/mol. By doing the following, I can calculate the approximate Delta H (only in kJ) for reaction 1:

Following the equation of Heat = Mass * Specific Heat (c) * Delta T, we get:

(Note, here I add the two masses of HCl and the solids, and then use the specific heat of water. I understand this holds quite a large uncertainty. If anybody has a better idea, please say so. I am also really unsure on what I do after calculating the heat, ie. when I invert the sign of the heat form + to - and vica versa. Is this correct?)

For NaHCO(3):
Mass = 0.101021 kg
Specific Heat (water) 4186 J/(kg * K)
Delta T = 1 K

Heat = 422.87 J. As this is an exothermic reaction, it becomes -422.87 J

For Na(2)CO(3):
Mass = 0.100905 kg
Delta T = -0.3 K

Heat = -126.71 J. As this is an endothermic reaction, it becomes +126.71 J.

Then, by doing the same to these numbers as is mentioned in Part 2 (the reactions), I end up with (-422.87 * 2) + (126.71*-1) = -970.71 J = -0.971 kJ!

But this however, is just the enthalpy change for the reaction. Not the molar enthalpy change...
Any comments on this would be absolutely wonderful, and greatly appreciated!
 
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  • #2
The units for molar enthalpy change are kJ/mol. You have the KJ part for a reaction containing 0.001021 kg of NaHCO3. (the reaction where the delta T was 1K, -422.87J) Convert this to moles and you have the molar enthalpy of that part.
You have the KJ part for a reaction consisting of 0.100905 kg of Na2CO3. (the reaction where delta T was -0.3K, 126.71J) Convert this to moles and you have the molar enthalpy of that part.

ONLY THEN CAN YOU SUBTRACT THE ENTHALPIES!

It doesn't do you any good to subtract the enthalpies from two reactions that contain different amounts of materials (as you have done in your OP).
I also assume that the CO2 gas was in thermal equilibrium with the solution before it bubbled away. That is, the evolved CO2 didn't carry away any heat energy ... You have also confounded the heats of reaction with the heats of solution. (a minor point)
 
  • #3
Thanks! I believe I've got it now. :)

Anyway, it'll have to wait. I'm off to Kaliningrad in Russia with class now.

Me and a couple of friends talked a bit, but your comment really cleared things up. Thank you very much!
 

FAQ: Hess Law: Molar Enthelpy Change for Decomposition

1. What is Hess Law?

Hess Law is a thermodynamic principle that states the total enthalpy change for a chemical reaction is independent of the pathway by which the reaction occurs.

2. How is Hess Law related to molar enthalpy change for decomposition?

Hess Law can be used to calculate the molar enthalpy change for decomposition by using the known enthalpy changes for individual reactions to determine the overall enthalpy change for the decomposition reaction.

3. What is the importance of molar enthalpy change for decomposition?

Molar enthalpy change for decomposition is important because it allows us to understand the energy changes associated with a chemical reaction. It also helps us to predict the feasibility and direction of a reaction.

4. How do you calculate molar enthalpy change for decomposition using Hess Law?

To calculate the molar enthalpy change for decomposition using Hess Law, you need to first determine the individual enthalpy changes for the reactions involved in the decomposition. Then, you can use the law to add or subtract these enthalpy changes to determine the overall enthalpy change for the decomposition.

5. Can Hess Law be applied to any chemical reaction?

Yes, Hess Law can be applied to any chemical reaction as long as the enthalpy changes for the individual reactions involved are known. It is a general principle that applies to all reactions, regardless of their complexity.

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