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physics20
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Why does the period of oscillation for a mass on a spring depend on its mass? (while in other situations, like a simple pendulum, the mass seems to be unimportant)
This is a little confusing and mostly not true.hotvette said:Reason is the amount of spring deflection is proportional to the attached mass. If mass is very small, the spring doesn't deflect very much and takes a much short time to complete a cycle than if the mass was large.
The period of oscillation for a mass on a spring is the amount of time it takes for the mass to complete one full cycle of motion. It is typically measured in seconds.
The period of oscillation is directly proportional to the square root of the mass of the object. This means that as the mass increases, the period also increases.
The period of oscillation can be affected by various factors such as the stiffness of the spring, the amplitude of the oscillation, and the presence of external forces such as friction.
The period of oscillation can be calculated using the equation T = 2π√(m/k), where T is the period, m is the mass of the object, and k is the spring constant.
No, the period of oscillation for a mass on a spring is not affected by the gravitational force. This is because the gravitational force only acts on the mass in a vertical direction, while the spring force acts in the opposite direction, resulting in a constant period of oscillation.