- #1
math_guy314
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Homework Statement
I am asked to solve a coupled system of 5 ODEs. There is also a function, f, which describes the release of carbon dioxide over time. I am given the release rates at certain values of t and asked to interpolate for other values of t in the interval [1000 3000]. After solving, I am asked to plot f as a subplot on top of y(1).
Homework Equations
The differential equations are shown in the code below. In my MATLAB code, I use g instead of dy/dt. The other terms are contants, etc ... I don't really have a question about these. It's more about the MATLAB code itself.
dy(1)/dt=(ps-y(1))/d+f/mu1;
dy(2)/dt=((y(3)-y(2))*w-k1-(ps-y(1))*mu2/d)/vs;
dy(3)/dt=(k1-(y(3)-y(2))*w)/vd;
dy(4)/dt=((y(5)-y(4))*w-k2)/vs;
dy(5)/dt=(k2-(y(5)-y(4))*w)/vd;
The Attempt at a Solution
function g = carbon(t,y)
%constants
d=8.64;
mu1=495;
mu2=.0495;
vs=0.12;
vd=1.23;
w=.001;
k1=.000219;
k2=.0000612;
k3=.997148;
k4=.0679;
%equations describing equilibrium between carbon dioxide and carbonate
%dissolved in the shallow ocean
h=(y(2)-((y(2))^2-k3*(y(4))*(2*(y(2))-y(4)))^.5)/k3;
c=(y(4)-h)/2;
ps=k4*h^2/c;
%interpolation function for carbon dioxide rate
yr=[1000 1850 1950 1980 2000 2050 2080 2100 2120 2150 2225 2300 2400 2500 3000];
data=[0 0 1 4 5 8 10 10.5 10 8 3.5 2 0 0 0];
f=interp1(yr,data,t,'pchip');
%differential equations
g=zeros(5,1);
g(1)=(ps-y(1))/d+f/mu1;
g(2)=((y(3)-y(2))*w-k1-(ps-y(1))*mu2/d)/vs;
g(3)=(k1-(y(3)-y(2))*w)/vd;
g(4)=((y(5)-y(4))*w-k2)/vs;
g(5)=(k2-(y(5)-y(4))*w)/vd;
end
I tried typing this in the command window:
%solution
[T,Y]=ode15s(@carbon,[1000 3000],[1 2.01 2.23 2.2 2.26]);
%graph
subplot(2,1,1);
plot(t,f)
xlabel('Time, t', 'fontsize', 14)
ylabel('Carbon Dioxide Release Rate, f(t)', 'fontsize', 14)
subplot(2,1,2);
plot(t,Y(:,1));
xlabel('Time, t', 'fontsize', 14)
ylabel('Partial Pressure of Carbon Dioxide, p(t)', 'fontsize', 14)
The problem is that this is my first time using MATLAB and I am not getting my function to run properly. Can someone point me in the right direction?