- #1
moonman239
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Deal or No Deal -- Odds of a better deal and most likely deal?
Suppose I am playing "Deal or No Deal." Assume that the banker's offers always equal the average value of the remaining cases. I have 5 cases remaining. The values of the cases are as follows:
$.01
$5
$10
$50,000
$100,000
thus resulting in an average of $12,003.002. If played another round, I'd have to choose 4 cases. What are the odds of getting a better offer on the next round? What offer would I be most likely to receive?
2. The attempt at a solution
First, I would figure out how many cases had values that were below the median (which is $50, in this case). Call that number x. Then the odds of a better deal on the next round equals x / n! * 4, where n is the number of remaining cases.
As for my other question, I don't know the answer.
Homework Statement
Suppose I am playing "Deal or No Deal." Assume that the banker's offers always equal the average value of the remaining cases. I have 5 cases remaining. The values of the cases are as follows:
$.01
$5
$10
$50,000
$100,000
thus resulting in an average of $12,003.002. If played another round, I'd have to choose 4 cases. What are the odds of getting a better offer on the next round? What offer would I be most likely to receive?
2. The attempt at a solution
First, I would figure out how many cases had values that were below the median (which is $50, in this case). Call that number x. Then the odds of a better deal on the next round equals x / n! * 4, where n is the number of remaining cases.
As for my other question, I don't know the answer.