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A 280000-kg wood block is firmly attached to a very light horizontal spring, as shown in the figure . The block can slide along a table where the coefficient of friction is 0.30. A force of 22 N compresses the spring .18m .
If the spring is released from this position, how far beyond its equilibrium position will it stretch at its first maximum extension?
I used 1/2 kx^2 = mew mg(x+D)
D is the distance the block travels
D= ((2*mew*mg)/k) -x
didnt come up with the right answer and I don't know why..Please help??
If the spring is released from this position, how far beyond its equilibrium position will it stretch at its first maximum extension?
I used 1/2 kx^2 = mew mg(x+D)
D is the distance the block travels
D= ((2*mew*mg)/k) -x
didnt come up with the right answer and I don't know why..Please help??