- #1
gsingh2011
- 115
- 1
Say you have the diff eq. x'=2x(x-13); x(0)=20. After separating and integrating we get,
ln|(x-13)/x|=26t+C
From here, we raise e to the power of each side to get rid of the natural log. Does this get rid of the absolute value signs? If so, why? If not, why is there only one solution (as dictated by wolfram alpha)?
ln|(x-13)/x|=26t+C
From here, we raise e to the power of each side to get rid of the natural log. Does this get rid of the absolute value signs? If so, why? If not, why is there only one solution (as dictated by wolfram alpha)?