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torquerotates
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The formula for calculating this probability is P(k heads in n flips) = (n choose k) * (0.5)^k * (0.5)^(n-k), where (n choose k) is the combination formula n!/(k!(n-k)!).
There are 2^n possible outcomes when flipping a fair coin n times. This is because for each flip, there are 2 possible outcomes (heads or tails) and these outcomes are independent of each other.
The probability of getting all heads in n flips of a fair coin is (0.5)^n. This is because each individual flip has a 0.5 probability of landing on heads, and these probabilities are multiplied together since the flips are independent events.
No, the probability of getting k heads in n flips cannot be greater than 1. This is because probabilities are always between 0 and 1, and the sum of all possible outcomes must equal 1. If the probability for a specific outcome is greater than 1, it would imply that the sum of all probabilities is greater than 1, which is not possible.
The number of flips (n) has a direct impact on the probability of getting k heads. As n increases, the probability of getting k heads also increases. This is because with more flips, there are more possible outcomes and a higher chance of getting the desired outcome (k heads). Additionally, as n increases, the probability of getting all heads (or all tails) decreases, while the probability of getting an equal number of heads and tails (e.g. half and half) increases.