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devon10
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It has been years scene I have taken a math class and I need help to see if I am setting the equation up correctly and if I have solved the problem correctly.
Diethyl ether has ∆Hvap of 29.1kJ/mol and a vapor pressure of 0.703 atm at 25.0 C. What is its vapor pressure at 95.0 C?
I converted the temp to K and kJ to J
In P2/P1=delta H vaporization/R (1/T2- 1/T1)
rearranged to
P2/P1= antilog (delta H vap/R (1/T2- 1/T1))
Then muliply by P1
P2= P1 antilog (delta H vap/R (1/T2- 1/T1))
antilog is also exp so...
P2= P1 exp(delta H vap/R (1/T2- 1/T1))
P2= .703 atm exp (29100/8.3145 (1/368-1/298)
P2= 2.19 atm
Diethyl ether has ∆Hvap of 29.1kJ/mol and a vapor pressure of 0.703 atm at 25.0 C. What is its vapor pressure at 95.0 C?
I converted the temp to K and kJ to J
In P2/P1=delta H vaporization/R (1/T2- 1/T1)
rearranged to
P2/P1= antilog (delta H vap/R (1/T2- 1/T1))
Then muliply by P1
P2= P1 antilog (delta H vap/R (1/T2- 1/T1))
antilog is also exp so...
P2= P1 exp(delta H vap/R (1/T2- 1/T1))
P2= .703 atm exp (29100/8.3145 (1/368-1/298)
P2= 2.19 atm