- #1
skateza
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Homework Statement
A passenger on the ferris wheel described in problem 18 (Problem 18: Fairgoers ride a Ferris wheel with a radius of 5.00m The wheel completes one revolution every 32.0s) drops his keys when he is on he way up and at the 10 o'clock position. Where do the keys land relative to the base of the ride?
Also: the diagram reveals the ferris wheel is 1.75m above the ground, and the center of the wheel is = base of the ride.
Homework Equations
all projectile motion equations
The Attempt at a Solution
I found the solution to be 58.0cm but I am pretty sure i didn't do it right. my steps were
1)Setup a diagram using the ten o'clock position to be 30degrees with a hypotenuse of 5m.
2)Found dx
3)t=(1/12)<rotation of wheel*(32s)<How long for the whole wheel to rotate
4) Found Vox
5) Found Voy
6) Used Voy in y(t) equation, where y(t)=0, gave me a quadratic i solved for t=3.44s (Supposing 0 = ground)
7) found x(3.44)
8) Subtracted the distance from center of the wheel from the radius
=58.0cm to the right of the base.
My intuition tells me i did something wrong at the start. My teacher told me today, the radius vector is perpinduclar to the Vo vector, so i think i can use that with pythag to find Vo somehow, any insight?