- #1
Lobotomy
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There is 5 players with 5 dices each = 25 throws per game
Whats the probability that there is X dices with the value Y(1-6) on the table.
for example. probability for 8 three's
this is calculated through the binomial theorem right?
http://en.wikipedia.org/wiki/Binomial_theorem
where n=25, k=8 och p=1/6calculating the probability of having X dices with the same value could be calculated with the above times six right?
so far so good.
now it gets a bit more complicated.
how to calculate:
how many dices of the same value is the most probable result? (assuming all 25 dices has been thrown)
Also, conditional probability:
i know that i have got Z dices with the same value (1-6 it doesn't matter which value). What is now the most probable result of the number of dices with the same value on the table?(i know my own result, but i don't know the 4 other players result)for instance: i get 4 three's. what is the most likely number of three's on the table totally of the 25dices?please refer to probability theory and distributions if you know them.
Whats the probability that there is X dices with the value Y(1-6) on the table.
for example. probability for 8 three's
this is calculated through the binomial theorem right?
http://en.wikipedia.org/wiki/Binomial_theorem
where n=25, k=8 och p=1/6calculating the probability of having X dices with the same value could be calculated with the above times six right?
so far so good.
now it gets a bit more complicated.
how to calculate:
how many dices of the same value is the most probable result? (assuming all 25 dices has been thrown)
Also, conditional probability:
i know that i have got Z dices with the same value (1-6 it doesn't matter which value). What is now the most probable result of the number of dices with the same value on the table?(i know my own result, but i don't know the 4 other players result)for instance: i get 4 three's. what is the most likely number of three's on the table totally of the 25dices?please refer to probability theory and distributions if you know them.