- #1
Mindstein
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Homework Statement
A 9.00-kg hanging object is connected, by a light, inextensible cord over a light, frictionless pulley, to a 5.00-kg block that is sliding on a flat table. Taking the coefficient of kinetic friction as .200, find the tension in the string
Homework Equations
F = ma
The Attempt at a Solution
Fk = ma
a = (9.8 N friction force)/(5.00 kg) = 1.96 which is approximately 2
ΣFx= T - Fk = ma
T = Fk + ma
T = (9.8N) + total mass 14N(1.96 m/s^2)
T = 37.24 or if you use 2 for the acceleration you get 37.8 which is the right answer
Did I do this right?
Please help me to understand why.