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pinkyjoshi65
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Circular Motion--Quick Question
A ferris wheel has a radius of 15 m and a period of 60 s is shown below. Find the Fnet at points B and D if the rider has a mass of 60 kg.
Ok, so this is a solved problem from a physics textbook.
This is the solution given in the textbook.
At B
Fnet = Fc - Fg (since they act in the same direction)
At D
Fnet = Fc + Fg (since they act in the different directions)
Solution
At B:
Fnet = Fc - Fg = 686 N - 9.9 N = 676 N
At D:
Fnet = Fc + Fg = 686 N + 9.9 N = 696 N
They found Fc by using 4pi^2rm/T^2
Heres where the problem arises.
I think that this solution is wrong.
How I solved it:
I took the direction in which tension acts as positive.
So at B(at top of the wheel)
Net force= Fc+Fg
And at D(at the bottom of the wheel)
Net force= Fc-Fg
Am I right?
A ferris wheel has a radius of 15 m and a period of 60 s is shown below. Find the Fnet at points B and D if the rider has a mass of 60 kg.
Ok, so this is a solved problem from a physics textbook.
This is the solution given in the textbook.
At B
Fnet = Fc - Fg (since they act in the same direction)
At D
Fnet = Fc + Fg (since they act in the different directions)
Solution
At B:
Fnet = Fc - Fg = 686 N - 9.9 N = 676 N
At D:
Fnet = Fc + Fg = 686 N + 9.9 N = 696 N
They found Fc by using 4pi^2rm/T^2
Heres where the problem arises.
I think that this solution is wrong.
How I solved it:
I took the direction in which tension acts as positive.
So at B(at top of the wheel)
Net force= Fc+Fg
And at D(at the bottom of the wheel)
Net force= Fc-Fg
Am I right?