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Homework Statement
If a 0.390 mM solution of MnO41- has an absorbance of 0.585 at 525 nm in a 1.000 cm cell. What is the concentration of a MnO41- solution that has absorbance of 0.330 in the same cell at that wavelength?
Homework Equations
The Attempt at a Solution
c(1) =concentration =.390 *10^-9 M
wavelength = 525*10^-9 m
pathlength = 1*10^-2 m
A(1)= absorbance = .585
A(2) = .330
I think the wavelength and pathlength are irrelevant to finding the concentration of (MnO4)1-
A(1)/A(2)= c(1)/c(2) => c(2)=c(1)*A(2)/A(1)
C(2)= (.330) *(.390*10^-9)/(.585) = 2.20*10^-9
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