- #1
exitwound
- 292
- 1
1. Homework Statement , from my crappy textbook
2. Homework Equations barely explained in my crappy textbook
Q=CV
[itex]C=\epsilon A/d[/itex]
3. The Attempt at a Solution that should be easy but the textbook is crap
Before squeezing:
Simplify the circuit by combining the two capacitors in parallel:
[itex]C_{12}=C_1 + C_2[/itex]
[itex]C_{12}=7x10^-6 + 7x10^-6 = 14x10^-6 F[/itex]
[itex]Q=CV[/itex]
[itex]Q=C_{12}V[/itex]
[itex]Q=(14x10^-6)(24)=3.36x10^-4 C[/itex]
After Squeezing:
[itex]C=\epsilon A/d[/itex]
[itex]2C=\epsilon A/(d/2)[/itex]
[itex]C=(7x10^-6)(2)=14x10^-6 F[/itex]
[itex]C_{12}=14x10^-6 + 7x10^-6 = 21x10^-6 F[/itex]
[itex]Q=(21x10^-6)(24)=5.04x10^-4 C[/itex]
Am I even close?
At this point, I have absolutely no idea what the problem is asking. Did I mention this book is terrible? Aren't both questions asking the exact same thing?? This is ridiculous.
2. Homework Equations barely explained in my crappy textbook
Q=CV
[itex]C=\epsilon A/d[/itex]
3. The Attempt at a Solution that should be easy but the textbook is crap
Before squeezing:
Simplify the circuit by combining the two capacitors in parallel:
[itex]C_{12}=C_1 + C_2[/itex]
[itex]C_{12}=7x10^-6 + 7x10^-6 = 14x10^-6 F[/itex]
[itex]Q=CV[/itex]
[itex]Q=C_{12}V[/itex]
[itex]Q=(14x10^-6)(24)=3.36x10^-4 C[/itex]
After Squeezing:
[itex]C=\epsilon A/d[/itex]
[itex]2C=\epsilon A/(d/2)[/itex]
[itex]C=(7x10^-6)(2)=14x10^-6 F[/itex]
[itex]C_{12}=14x10^-6 + 7x10^-6 = 21x10^-6 F[/itex]
[itex]Q=(21x10^-6)(24)=5.04x10^-4 C[/itex]
Am I even close?
At this point, I have absolutely no idea what the problem is asking. Did I mention this book is terrible? Aren't both questions asking the exact same thing?? This is ridiculous.