- #1
aisha
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Check please Eqn of Circle with diameter end points(1,2) and (3,-6)
Find the equation of a circle with a diameter that has end points P(1,2) and Q(3,-6)
I know the equation for a circle in general form is [tex]x^2+y^2=r^2 [/tex]
First I found the distance between the two points given because this also equals the diameter.
I used point P as x1,y1 and Q as x2,y2 and subbed these points into the distance equation.
I got Distance=Diameter=sqrt(68) I took half of this to get the radius. 5.83 and then I put this into the equation for a circle and squared it to get 33.99
My final equation of a circle for this question is [tex] x^2+y^2=34 [/tex]
Can someone please check my answer and tell me if I went wrong anywhere?
Find the equation of a circle with a diameter that has end points P(1,2) and Q(3,-6)
I know the equation for a circle in general form is [tex]x^2+y^2=r^2 [/tex]
First I found the distance between the two points given because this also equals the diameter.
I used point P as x1,y1 and Q as x2,y2 and subbed these points into the distance equation.
I got Distance=Diameter=sqrt(68) I took half of this to get the radius. 5.83 and then I put this into the equation for a circle and squared it to get 33.99
My final equation of a circle for this question is [tex] x^2+y^2=34 [/tex]
Can someone please check my answer and tell me if I went wrong anywhere?