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Lucasss84
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Why the roots of Eq. x^2 + a*x + b = 0 and of Eq. x + a*Sqrt[x] + b = 0 are not identically? How can I expand the second Eq. in simple fractions: x + a*Sqrt[x] + b = ... ?
Thank you. Lucas
Thank you. Lucas
Lucasss84 said:Why the roots of Eq. x^2 + a*x + b = 0 and of Eq. x + a*Sqrt[x] + b = 0 are not identically?
How can I expand the second Eq. in simple fractions: x + a*Sqrt[x] + b = ... ?
The two equations have different forms and thus have different methods for solving them. The first equation is a quadratic equation, which can be solved using the quadratic formula. The second equation is a radical equation, which requires isolating the square root term and then squaring both sides to eliminate the radical.
Yes, the roots of both equations can be complex numbers. This occurs when the discriminant, b^2 - 4ac, is negative in the quadratic equation, or when the radicand, x, is negative in the radical equation.
The roots of the quadratic equation can be found using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. The roots of the radical equation can be found by isolating the square root term and then squaring both sides to eliminate the radical.
The coefficient a represents the coefficient of the x^2 term in the quadratic equation, and the coefficient of the square root term in the radical equation. It affects the shape and position of the graph of the equation. The coefficient b represents the constant term, which affects the y-intercept of the graph.
Yes, there are special cases for both equations. In the quadratic equation, if the coefficient a is equal to 0, then the equation becomes a linear equation and the solution is a single root. In the radical equation, if the coefficient a is equal to 0, then the equation becomes a pure quadratic equation and can be solved using the quadratic formula.