- #1
A_Munk3y
- 72
- 0
Titration question 2! equivalence points. Am i right?
this is the originial question.
A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?
and i got 86.63 g/mol. I have already made sure that it is right.
the question continues,
If the pH of the weak acid in question 1 (above) is 4,34 after 8.40 ml of the NaOH was added, what is the Ka of the acid?
i think i remember this. At the half equivalence point, PH=PKa
since PH=Pka at half equivalence point, the PH=10-4.38
giving me 4.17x10-5
am i right? :)
Homework Statement
this is the originial question.
A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?
and i got 86.63 g/mol. I have already made sure that it is right.
the question continues,
If the pH of the weak acid in question 1 (above) is 4,34 after 8.40 ml of the NaOH was added, what is the Ka of the acid?
Homework Equations
i think i remember this. At the half equivalence point, PH=PKa
The Attempt at a Solution
since PH=Pka at half equivalence point, the PH=10-4.38
giving me 4.17x10-5
am i right? :)