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ob123
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Homework Statement
Suppose the water at the top of Niagara Falls has a horizontal speed of 1.42 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 61.8 ° angle below the horizontal?
Homework Equations
Not sure
The Attempt at a Solution
Initial velocity(u) of Niagara falls = 1.42 m/s
Angle(θ) at which it strikes the ground = 61.8o
Formula used: tan(61.8) = sq.rt(2*9.8*x/1.42)
I solved for x and got .252 m but the answer is wrong. Now I have no idea on what to do. Any help would be appreciated. Thank you.