- #1
yoohoo
- 4
- 0
Statics Equilibrium Problem -- 3 Force body in equilibrium
Q: A T-shaped bracket supports a 150-N load as shown. Determine the reactions at A and C when (a) alpha=90o, (b) alpha =45o
A: (a)A=150N going down, C=167.7N,63.4degrees (b)A= 194.5N going down; C=253N, 77.9 degrees
Here's the diagram from the book:
http://www.glowfoto.com/viewimage.php?img=23-165339L&rand=2124&t=jpg&m=07&y=2010&srv=img6
sum of forces (it is in equilibrium) and force triangle
I made a force triangle where I found the angle 23.565 degrees (which makes sense since they give 63.4 degrees in the textbook). However, using the sine law I expected to come out with the right answer using:
150N/sin(23.565) = A/sin(63.4)
and
150N/sin(23.565) = C/sin(90)
... instead I keep coming out with A and C values that are double what they should be. Ie. A = 300 N and C = 335.4 N
What am I doing wrong? Am I approaching it the wrong way?
Thanks in advance! :)
Homework Statement
Q: A T-shaped bracket supports a 150-N load as shown. Determine the reactions at A and C when (a) alpha=90o, (b) alpha =45o
A: (a)A=150N going down, C=167.7N,63.4degrees (b)A= 194.5N going down; C=253N, 77.9 degrees
Here's the diagram from the book:
http://www.glowfoto.com/viewimage.php?img=23-165339L&rand=2124&t=jpg&m=07&y=2010&srv=img6
Homework Equations
sum of forces (it is in equilibrium) and force triangle
The Attempt at a Solution
I made a force triangle where I found the angle 23.565 degrees (which makes sense since they give 63.4 degrees in the textbook). However, using the sine law I expected to come out with the right answer using:
150N/sin(23.565) = A/sin(63.4)
and
150N/sin(23.565) = C/sin(90)
... instead I keep coming out with A and C values that are double what they should be. Ie. A = 300 N and C = 335.4 N
What am I doing wrong? Am I approaching it the wrong way?
Thanks in advance! :)
Last edited by a moderator: