- #1
Jeff Ford
- 155
- 2
I am working to prove that this function is continuous at [itex] x = 2 [/itex]
[tex] f(x) = 9x–7 [/tex]
To do this I know that I have to show that [itex] \vert f(x)–f(a) \vert < \epsilon[/itex] and that [itex] \vert x-a < \delta \vert [/itex]
I tried to come up with a relationship between [itex] \vert x-2 \vert [/itex] and [itex] \epsilon [/itex] so I could get an appropriate number to choose for [itex] \delta [/itex]
This is as far as I got
[tex] \vert f(x)–f(a) \vert < \epsilon [/tex]
[tex] \vert 9x–7 \vert < \epsilon [/tex]
I’m stuck. All of the examples the text shows give equations where it is easy to factor out the [itex] \vert x-a \vert [/itex] term.
A push in the right direction would be appreciated.
[tex] f(x) = 9x–7 [/tex]
To do this I know that I have to show that [itex] \vert f(x)–f(a) \vert < \epsilon[/itex] and that [itex] \vert x-a < \delta \vert [/itex]
I tried to come up with a relationship between [itex] \vert x-2 \vert [/itex] and [itex] \epsilon [/itex] so I could get an appropriate number to choose for [itex] \delta [/itex]
This is as far as I got
[tex] \vert f(x)–f(a) \vert < \epsilon [/tex]
[tex] \vert 9x–7 \vert < \epsilon [/tex]
I’m stuck. All of the examples the text shows give equations where it is easy to factor out the [itex] \vert x-a \vert [/itex] term.
A push in the right direction would be appreciated.